Practice Problems: Measures of Variability - Answer

Bailey has been playing golf on the weekends for the past three years. Recently, she started keeping track of her recorded scores. Her scores for June and July at her favorite 9-hole (par 36) golf course are provided below.

X X2
563136
492401
452025
421764
421764
411681
411681
411681
411681
401600
401600
391521
391521
381444
381444
361296
361296
34 1156
73830692


Standard Deviation

S = 18 (30692) - 7382
18 (18-1)

S = 5.0526638

Variance

The variance is 25.529412. The standard deviation is 5.0526638. The variance is the square of the standard deviation. 5.0526638 squared is equal to 25.529412.

S2 = 25.529412

Range

The range is 22. The high score is 56; the low score is 34. 56 - 34 = 22.

Range = 22

What does this information tell you about the variability in Bailey's golf game?

Bailey's golf game appears to be fairly consistent (at least by my standards in relation to my golf game). She is somewhat consistently within 5 strokes of her mean performance.


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